How can we find the intersection between two planes in higher dimensions (4d space and above)?

Technical Source
2 min readJul 4, 2023

--

How can we find the intersection between two planes in higher dimensions (4d space and above)? For example we have the following 2 planes in 4d:

Plane 1

P1 =[252716585.970010 -136769230.769231 0 0]; 
P2 =[ -136769230.769231 252716585.970010 -136769230.769231 0];
P3= [0 -136769230.769231 252716585.970010 -136769230.769231];
P4 = [0 0 -136769230.769231 126358292.985005];

Plane 2

P11= [191269260.712188 -136769230.769231 0 0]; 
P22=[ -136769230.769231 259653876.096803 -136769230.769231 0];
P33= [0 -136769230.769231 259653876.096803 -136769230.769231];
P44=[0 0 -136769230.769231 129826938.048402];

NOTE:-

Matlabsolutions.com provide latest MatLab Homework Help,MatLab Assignment Help , Finance Assignment Help for students, engineers and researchers in Multiple Branches like ECE, EEE, CSE, Mechanical, Civil with 100% output.Matlab Code for B.E, B.Tech,M.E,M.Tech, Ph.D. Scholars with 100% privacy guaranteed. Get MATLAB projects with source code for your learning and research.

In general, intersections of two hyperplanes would be expressed algebraically by a 2xN set of linear equations Aeq*x=beq. A geometric description can be made in terms of an origin vector, which gives the position of some point in the intersection space, and a set of direction vectors which span the linear space parallel to it. Example:

Aeq=[1,2,3,4;
5,6,7,8];
beq=[5;7];
assert( rank([Aeq,beq])==rank(Aeq) , 'Hyperplanes do not intersect')
origin = pinv(Aeq)*beq
origin = 4×1
-1.0000
-0.2500
0.5000
1.2500
directions = null(Aeq)

SEE COMPLETE ANSWER CLICK THE LINK

--

--

Technical Source

Simple! That is me, a simple person. I am passionate about knowledge and reading. That’s why I have decided to write and share a bit of my life and thoughts to.