how do I find the x-axis value from my yline intercept on my acceleration curve?

Technical Source
2 min readNov 4, 2023

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I have an acceleration curve and i need to find the 0–60mph (0–26.8224m/s) Stuck on how to get there, currently only have a yline that shows where 26.8224m/s along the y-axis. Please help! Here’s my code and a picture of the graph:

figure(6)
P1 = plot(tout,yout(:,1));
xlabel('Time (s)')
ylabel('Velocity (m/s)')
grid on
set(P1,'linewidth',2)
title('Acceleration Curve')
yline(26.8224)

NOTE:-

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% some data:
tout = (0:60).';
yout = 10*log(tout+1);
y_val = 26.8224;
% your plot:
P1 = plot(tout,yout(:,1),'linewidth',2);
xlabel('Time (s)')
ylabel('Velocity (m/s)')
grid on
title('Acceleration Curve')
yline(y_val)
% find the t value where y is y_val:
t0 = interp1(yout(:,1),tout,y_val)
t0 = 13.6259
% plot a vertical red line to that point on the curve:
hold on
plot([t0,t0],[0,y_val],'--r')

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Technical Source
Technical Source

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